1-3600x^2=0

Solution for 1-3600x^2=0 equation:

1-3600x^2=0

a = -3600; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-3600)·1
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-3600}=\frac{-120}{-7200}
=1/60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-3600}=\frac{120}{-7200}
=-1/60
$